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600+2x^2-70x=0
a = 2; b = -70; c = +600;
Δ = b2-4ac
Δ = -702-4·2·600
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-10}{2*2}=\frac{60}{4} =15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+10}{2*2}=\frac{80}{4} =20 $
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